XHS 2022 4Express AM MYE
XHS 2022 4Express AM MYE
Secondary 4
5 marks
- The equation of a curve is \(y = 3x\sqrt{5 + x^2}\). Find the gradient(s) of the curve at the point(s) where it crosses the line \(y = 6x\).[5]
Solution:
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Answer:(iii) The only intersection is \((0,0)\), where the gradient is \(3\sqrt5\).
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