The gradient of a curve at the point $(x, y)$ is proportional to $y^2$. The curve passes through

Question

The gradient of a curve at the point $(x, y)$ is proportional to $y^2$. The curve passes through the points $(0, -2)$ and $(1, \frac{2}{3})$. Find the equation of the curve.

Accepted Answer

$y=\dfrac2{4x-1}$, $x\ne\dfrac14$

Word problems: recovering function

Word problems: recovering function

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