Velocity from acceleration at an intermediate time

Velocity from acceleration at an intermediate time

Secondary 4
7 marks
Original parallel to supplied A Math Kinematics references

A particle moves along a straight line with acceleration \(a=(4t-8)\text{ m s}^{-2}\). When \(t=1\), its velocity is \(5\text{ m s}^{-1}\) and its displacement from \(O\) is \(0\) metres.

  1. Find the velocity of the particle in terms of \(t\).[2]
  2. Show that the particle is never instantaneously at rest.[2]
  3. Find the distance travelled between \(t=1\) and \(t=4\).[3]

Solution:

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Answer:(i) \(v=2t^2-8t+11\text{ m s}^{-1}\) (ii) \(v=2(t-2)^2+3>0\), so never at rest (iii) \(15\text{ m}\)

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