In the diagram, \(OA\) is parallel to \(CB\) and \(SC\) is parallel to \(AB\). The position vectors of \(A\) and \(B\) relative to \(O\) are \(4\mathbf{a}\) and \(5\mathbf{b}\) respectively. It is given that \(OS : SB = 2 : 3\) and \(\overrightarrow{AT} = \frac{1}{3}\overrightarrow{TB}\).
Find, in terms of \(\mathbf{a}\) and \(\mathbf{b}\), the vectors
\(\overrightarrow{OS}\),
\(\overrightarrow{AS}\),
\(\overrightarrow{OT}\).
\(U\) is a point on \(OT\) such that \(OU : UT = 8 : 3\).
Express \(\overrightarrow{AU}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).
Hence write down two facts about \(A\), \(U\) and \(S\).
Prove that \(\Delta SBC\) is similar to \(\Delta BOA\).
Find
\(\frac{\text{Area of}\hspace{0.5em} \Delta SBC}{\text{Area of}\hspace{0.5em} \Delta BOA}\),
\(\frac{\text{Area of}\hspace{0.5em} \Delta OTA}{\text{Area of}\hspace{0.5em} \Delta OBA}\).