Vectors - Perpendicular Projection and Reflection in a Line

Vectors - Perpendicular Projection and Reflection in a Line

The line equation \(l:\mathbf{r}=\left( \begin{matrix} 5 \\ 2 \\ 0 \\ \end{matrix} \right)+\lambda \left( \begin{matrix} 1 \\ -2 \\ 2 \\ \end{matrix} \right)\). Find the position vector of the foot \(N\) of the perpendicular from \(A\left( \begin{matrix} 9 \\ 1 \\ 6 \\ \end{matrix} \right)\). Hence find the position vector of the image of \(A\) in the line \(l\).

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Answer:\(\overrightarrow{ON}=\begin{pmatrix}7\\-2\\4\end{pmatrix}\) \(\overrightarrow{OA'}=\begin{pmatrix}5\\-5\\2\end{pmatrix}\)

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