Relative to the origin \(O\), the position vectors of \(A\), \(B\) and \(C\) are \(\mathbf{a}\), \(\mathbf{b}\) and \(\mathbf{c}\) respectively where \(\mathbf{c}=2\mathbf{a}-3\mathbf{b}\). Given that \(\mathbf{a}\) is a unit vector, \(\left| \mathbf{b} \right|=5\) and the angle between \(\mathbf{a}\) and \(\mathbf{b}\) is \(\frac{2}{3}\pi \), show that the exact area of triangle \(ABC\) is \({\frac{5\sqrt{3}}{2} \mathrm{ units}^2}\)
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