The equation of line $l$ is given by $\mathrm{r}=\left( \begin{matrix}2\1\0 \\end{matrix} ight)+

Question

The equation of line $l$ is given by $\mathrm{r}=\left( \begin{matrix}2\1\0 \\end{matrix}ight)+\lambda \left( \begin{matrix}1\-2\1\\end{matrix} ight)$. The coordinates of points $A$ and $B$ are $\left( 1,3,-2 ight)$ and$(1,0,-2)$. Find the length of projection of $\overrightarrow{AB}$ on $l$.

Accepted Answer

$\sqrt{6}$ units\)

Unit 13.1 Worked Example 5

Unit 13.1 Worked Example 5

Video Solution:

Default solution