Vectors - Projection Lengths

Vectors - Projection Lengths

The equation of line \(l\) is given by \(\mathrm{r}=\left( \begin{matrix}2\\1\\0 \end{matrix}\right)+\lambda \left( \begin{matrix}1\\-2\\1\end{matrix} \right)\). The coordinates of points \(A\) and \(B\) are \(\left( 1,3,-2 \right)\) and \((1,0,-2)\). Find the length of projection of \(\overrightarrow{AB}\) on \(l\).

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Answer:Length of projection \(=\sqrt6\text{ units}\).

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