Vectors - Ratio Theorem and Section Formula

Vectors - Ratio Theorem and Section Formula

Secondary 4

In triangle \(AOB\), \(\overrightarrow{OA} = \mathbf{a}\) and \(\overrightarrow{OB} = \mathbf{b}\). \(C\) lies on \(AB\) such that \(AC:AB = 1:3\).

Express \(\overrightarrow{OC}\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\), giving your answer in the simplest form.

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Answer:\(\dfrac{2\mathbf a+\mathbf b}{3}\)

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