In triangle \(OAB\), \(C\) is on \(OA\), \(D\) is on \(AB\), such that \(BC\) intersects \(OD\) at \(E\). It is given that \(\overrightarrow{OE} = \frac{1}{2}\overrightarrow{OD}\), \(\overrightarrow{EB} = \frac{2}{3}\overrightarrow{CB}\), \(\overrightarrow{OA} = \mathbf{a}\) and \(\overrightarrow{OB} = \mathbf{b}\).

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