${{\Pi }_{1}}:\mathbf{r}\cdot\left(\begin{matrix}3\-6\1\\end{matrix}\right)=1$; \({{\Pi}_{2}}:2

Question

${{\Pi }_{1}}:\mathbf{r}\cdot\left(\begin{matrix}3\-6\1\\end{matrix}\right)=1$; ${{\Pi}_{2}}:2x-3y+z=10$

Accepted Answer

Intersecting, $9.9^\circ$, $\mathbf r=\begin{pmatrix}-9\0\28\end{pmatrix}+\lambda\begin{pmatrix}-3\-1\3\end{pmatrix}$

Vectors - Relationships Between Two Planes