Variable braking after a powered stage

A particle moves along a straight line with velocity \(v=6t-t^2\text{ m s}^{-1}\) for \(0\leq t\leq4\). At \(t=4\), a braking stage begins. If \(T\) seconds is the time measured from the start of braking, the acceleration is \(-(2+T)\text{ m s}^{-2}\).

1. Find the distance travelled during the first stage and the velocity at its end.[3]
2. Find the value of \(T\) at which the particle comes to rest.[3]
3. Find the total distance travelled before the particle comes to rest, giving your answer in surd form.[3]