Using Standardization to Solve μ and σ

Using Standardization to Solve μ and σ

The diameters of metal rods may be assumed to have a normal distribution with mean \(\mu\) cm and standard deviation \(\sigma\) cm. It was known that \(93\)% of all rods produced have diameters exceeding \(0.05\) m and \(6.5\)% have diameters exceeding \(0.052\) m, find the values of \(\mu\) and \(\sigma\).

Hence, find the probability that the diameter of a rod is between \(4.96\) cm and \(5.02\) cm.

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Answer:\(\mu=5.10\text{ cm}\), \(\sigma=0.0669\text{ cm}\); \(P(4.96<D<5.02)=0.101\)

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