Use the fact that $\frac{\mathrm{d}}{\mathrm{d}x}(\arctan 3x) = \frac{3}{1+9x^2}$ to find the

Question

Use the fact that $\frac{\mathrm{d}}{\mathrm{d}x}(\arctan 3x) = \frac{3}{1+9x^2}$ to find the coefficient of the third non-zero term of the Maclaurin series representation of $\arctan 3x$.

Accepted Answer

$\frac{243}{5}$, the coefficient of $x^5$.

Using standard series

Using standard series

Solution:

Solution locked