<p>In the figure, $\Delta ABC$ is an isosceles triangle.</p>
<div class="content-block"><figure class="question-figure aligncenter" style="text-align: center;"><img src="https://vocwkpgapvksartxhhor.supabase.co/storage/v1/object/public/question-images/pasted/1765171647648-3wy2rzdlz3x.png" style="max-width: min(400px, 100%); height: auto; display: block;" class="aligncenter custom-width" /></figure></div>
<p>Given that&nbsp;$AB=AC=15$cm and $BD=DC=12$cm, find</p>
<ol class="abc-list"><li><div class="list-item-paragraph">the length of $AD$,</div></li><li><div class="list-item-paragraph">the area of $\Delta ABC$.</div></li></ol>

In the figure, $\Delta ABC$ is an isosceles triangle.

Given that $AB=AC=15$cm and $BD=DC=12$cm, find

Using Pythagoras’ Theorem in an Isosceles Triangle

Using Pythagoras’ Theorem in an Isosceles Triangle

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