Two routes to an intersection

Two routes to an intersection

Secondary 4
6 marks
TGM Original Questions

In triangle \(OAB\), \(O,A,B\) are not collinear, \(\overrightarrow{OA}=\mathbf{a}\) and \(\overrightarrow{OB}=\mathbf{b}\). Point \(P\) is the midpoint of \(OA\), and \(Q\) lies on \(OB\) with \(OQ:QB=1:2\). The lines \(AQ\) and \(BP\) intersect at \(R\).

Let \(\overrightarrow{AR}=t\overrightarrow{AQ}\) and \(\overrightarrow{BR}=s\overrightarrow{BP}\).

  1. Express \(\overrightarrow{OR}\) using the route through \(A\), and then using the route through \(B\).[2]
  2. Find \(s\) and \(t\).[3]
  3. Find \(AR:RQ\).[1]

Solution:

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Answer:(a) \((1-t)\mathbf{a}+\dfrac t3\mathbf{b}\), \(\dfrac s2\mathbf{a}+(1-s)\mathbf{b}\) (b) \(s=\dfrac45,t=\dfrac35\) (c) \(3:2\)

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