In triangle \(OAB\), \(O,A,B\) are not collinear, \(\overrightarrow{OA}=\mathbf{a}\) and \(\overrightarrow{OB}=\mathbf{b}\). Point \(P\) is the midpoint of \(OA\), and \(Q\) lies on \(OB\) with \(OQ:QB=1:2\). The lines \(AQ\) and \(BP\) intersect at \(R\).
Let \(\overrightarrow{AR}=t\overrightarrow{AQ}\) and \(\overrightarrow{BR}=s\overrightarrow{BP}\).
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