IB Math HL Trigonometry Test 6 2018 P1 Q4

IB Math HL Trigonometry Test 6 2018 P1 Q4

IB Year 6 | Grade 12
7 marks
  1. Write down the minimum and maximum values of \(\pi\cos^2x\).[1]
  2. Solve \(\sqrt2\sin(\pi\cos^2x)=1\) for \(0\le x\le\pi\).[6]

Solution:

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Answer:(a) Minimum \(0\), maximum \(\pi\). (b) \(x=\frac{\pi}{6},\frac{\pi}{3},\frac{2\pi}{3},\frac{5\pi}{6}\).

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