<p>In triangle $ABC$, $AB=12$cm, $AC=5$ cm and $BC=13$ cm. </p>
<div class="content-block"><figure class="question-figure aligncenter" style="text-align: center;"><img src="https://vocwkpgapvksartxhhor.supabase.co/storage/v1/object/public/question-images/pasted/1765178122659-zv7b0k5saal.png" style="max-width: min(200px, 100%); height: auto; display: block;" class="aligncenter custom-width" /></figure></div>
<p>Given that angle $BAC=90{}^\circ $, state the value of </p>
<ol class="i-list"><li><div class="list-item-paragraph">$\sin \angle ACB$,</div></li><li><div class="list-item-paragraph">$\cos \angle ACB$,</div></li><li><div class="list-item-paragraph">$\tan \angle ACB$,</div></li><li><div class="list-item-paragraph">$\sin \angle CBA$,</div></li><li><div class="list-item-paragraph">$\cos \angle CBA$,</div></li><li><div class="list-item-paragraph">$\tan \angle CBA$.</div></li></ol>

In triangle $ABC$, $AB=12$cm, $AC=5$ cm and $BC=13$ cm. 

Given that angle $BAC=90{}^\circ $, state the value of 

Trigonometry of Triangle $ABC$ with Angle $BAC$ = $90{}^\circ $

Trigonometry of Triangle $ABC$ with Angle $BAC$ = $90{}^\circ $

Video Solution: