In $\Delta ABC$, $AB=7.5$ m and $\angle ACB=90{}^\circ $. $X$ lies on $CA$ such that

Question

In $\Delta ABC$, $AB=7.5$ m and $\angle ACB=90{}^\circ $. $X$ lies on $CA$ such that $XB=3$ m and $\angle XBC=43{}^\circ $. Find $\angle BAC$, the length of $XA$.

Accepted Answer

(i) 17.0 degrees; (ii) 5.13 m.

Trigonometry in Right Triangle \(ABC\) with Internal Point \(X\)

Trigonometry in Right Triangle \(ABC\) with Internal Point \(X\)

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