In triangle $PQR$, $PQ = 10\text{ cm}$, $QR = 7\text{ cm}$ and $\angle P = 30^\circ$. Find a

Question

In triangle $PQR$, $PQ = 10\text{ cm}$, $QR = 7\text{ cm}$ and $\angle P = 30^\circ$. Find all possible values of $\angle R$. Give answers to $1$ decimal place and explain why there can be two answers.[4]

Accepted Answer

$45.6^\circ$ or $134.4^\circ$. Both are possible because $30^\circ+R<180^\circ$ for each value.

Trigonometry

Trigonometry

Solution:

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