IB Math HL Trigonometry Test 4 2015 P1 Q4

IB Math HL Trigonometry Test 4 2015 P1 Q4

IB Year 6 | Grade 12
9 marks
  1. Solve \(\sin5x=\sin3x\) for \(-\frac{\pi}{2}\le x\le\frac{\pi}{2}\).[4]
  2. [5]
    1. Explain why \(\sin(-x)=-\sin x\).
    2. Hence solve \(\cos5x+\sin x=0\) for \(0\le x\le\pi\).

Solution:

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Answer:(a) \(x=-\frac{3\pi}{8},-\frac{\pi}{8},0,\frac{\pi}{8},\frac{3\pi}{8}\). (b)(ii) \(x=\frac{\pi}{8},\frac{\pi}{4},\frac{7\pi}{12},\frac{5\pi}{8},\frac{11\pi}{12}\).

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