IB Math HL Trigonometry Test 7 2018 P1 Q7

IB Math HL Trigonometry Test 7 2018 P1 Q7

IB Year 6 | Grade 12
10 marks
  1. Solve \(\sin2x=\sin3x\) for \(0\le x\le\pi\).[4]
  2. Solve \(\sqrt2\sin2x=\sin4x\) for \(0\le x\le\pi\).[6]

Solution:

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Answer:(a) \(x=0,\frac{\pi}{5},\frac{3\pi}{5},\pi\). (b) \(x=0,\frac{\pi}{8},\frac{\pi}{2},\frac{7\pi}{8},\pi\).

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