IB Math HL Trigonometry Test 1 2012 P2 Q5

IB Math HL Trigonometry Test 1 2012 P2 Q5

IB Year 6 | Grade 12
24 marks
  1. Using \(\sin(A+B)\) and suitable double-angle identities, prove \(\sin3\theta=3\sin\theta-4\sin^3\theta\).[3]
  2. Given \(\cos3\theta=4\cos^3\theta-3\cos\theta\), use \(\cos(A+B)\) with suitable \(A\) and \(B\) to prove \(\frac{\cos5\theta}{\cos\theta}=16\sin^4\theta-12\sin^2\theta+1\).[7]
  3. By considering \(\frac{\cos5\theta}{\cos\theta}=0\), solve \(16\sin^4\theta-12\sin^2\theta+1=0\) for \(0\le\theta<\pi\), giving answers in the form \(\frac{n\pi}{10}\), \(n\in\mathbb N\).[4]
  4. Find the four exact values of \(\sin\theta\) satisfying \(16\sin^4\theta-12\sin^2\theta+1=0\).[5]
    1. Hence show that \(\sin\frac{\pi}{10}=\sqrt{\frac{3-\sqrt5}{8}}\).[3]
    2. State the exact value of \(\sin\frac{7\pi}{10}\).[2]

Solution:

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Answer:(c) \(\theta=\frac{\pi}{10},\frac{3\pi}{10},\frac{7\pi}{10},\frac{9\pi}{10}\). (d) \(\sin\theta=\pm\sqrt{\frac{3-\sqrt5}{8}},\pm\sqrt{\frac{3+\sqrt5}{8}}\). (e)(ii) \(\sqrt{\frac{3+\sqrt5}{8}}\).

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