Points $B,C,D$ are collinear. Given $BC=4.5$ cm, $AC=9$ cm, $AD=14$ cm, \(\angle ACD=\angle

Question

Points $B,C,D$ are collinear. Given $BC=4.5$ cm, $AC=9$ cm, $AD=14$ cm, $\angle ACD=\angle AED=90^\circ$ and $\angle DAE=42^\circ$, calculate $4.5$ $9$ $14$ $B$ $C$ $D$ $A$ $E$ $42^\circ$ Give non-exact lengths and areas to 3 significant figures, and angles to 1 decimal place.

Accepted Answer

(a) $63.4^\circ$ (b) $40.0^\circ$ (c) $10.4$ cm.

Collinear-base compound with two right angles

Collinear-base compound with two right angles

Solution:

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