Triangles $ABC$ and $BCD$ share $BC$, with $\angle ABC=\angle BCD=90^\circ$. Given $AB=15$

Question

Triangles $ABC$ and $BCD$ share $BC$, with $\angle ABC=\angle BCD=90^\circ$. Given $AB=15$ cm, $\angle BAC=54^\circ$ and $\angle BDC=63^\circ$, find $BC$, $BD$. $AB=15$ $C$ $B$ $A$ $D$ $54^\circ$ $63^\circ$ Give non-exact lengths and areas to 3 significant figures, and angles to 1 decimal place.

Accepted Answer

(a) $20.6$ cm (b) $23.2$ cm.

Two right triangles sharing a side

Two right triangles sharing a side

Solution:

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