In the diagram, $AB = 4$ cm, $BC = 7.5$ cm, $AD = 5$ cm, $BD = 6.2$ cm and \(\angle BDC = 55

Question

In the diagram, $AB = 4$ cm, $BC = 7.5$ cm, $AD = 5$ cm, $BD = 6.2$ cm and $\angle BDC = 55^\circ$. Calculate $\angle ADB$, $\angle BCD$, the area of $ABCD$.

Accepted Answer

(i) $40.1^\circ$ (ii) $42.6^\circ$ (iii) $33.0\text{ cm}^2$

Trigonometry - Area of Triangle

Trigonometry - Area of Triangle

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