The figure shows a triangle $ABC$ where $BC=23$ cm, $K$ lies on $BC$ such that the leng

Question

The figure shows a triangle $ABC$ where $BC=23$ cm, $K$ lies on $BC$ such that the length of $BK$ is $135\%$ of the length of $KC$ and $\angle AKC=90{}^\circ $. Given that the area of $\Delta ABK$ is $68$ cm$^{2}$, find $\angle BAC$.

Accepted Answer

$\angle BAC=95.6^\circ$

Trigonometry and Geometry in Triangle \(ABC\)

Trigonometry and Geometry in Triangle \(ABC\)

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