In triangle $ABC$, $\angle A = 42^\circ$, $\angle B = 71^\circ$, and side \(a = BC = 8.5\text{

Question

In triangle $ABC$, $\angle A = 42^\circ$, $\angle B = 71^\circ$, and side $a = BC = 8.5\text{ cm}$. Find side $b = AC$ to $3\text{ s.f.}$ (Diagram not drawn to scale)[3]

Accepted Answer

$b=11.9\text{ cm}$ (3 s.f.)

Trigonometry

Trigonometry

Solution:

Solution locked