Show that \(\frac{2\tan{\theta}}{1 + \tan^2{\theta}}\) can be expressed as \(\sin{2\theta}\)
[3]Hence, solve the equation \(\frac{2\tan{\theta}}{1 + \tan^2{\theta}} = \frac{1}{2}\) for \(0^{\circ} \leq \theta \leq 180^{\circ}\).
[5]Let \(x = \tan{ \left(22 \frac{1}{2} ^{\circ} \right)}\).
Use the result from part (a) to show that \(x^2 - 2\sqrt{2}x + 1 = 0\).
[4]Hence, find the exact value of \(\tan{ \left( 22 \frac{1}{2}^{\circ} \right) } \).
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