Trigonometry

Trigonometry

Secondary 4

A right-angled triangular frame has hypotenuse \(6\text{ cm}\) and acute angle \(\theta\), where \(0^\circ<\theta<90^\circ\).

Let its perimeter be \(P\text{ cm}\).

  1. Show that \(P=6+6\sin\theta+6\cos\theta. \)

  2. Find the exact maximum perimeter and the corresponding \(\theta\).

  3. Find the values of \(\theta\) when \(P=14\text{ cm}\).

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Answer:\(P=6+6\sqrt2\sin(\theta+45^\circ)\); maximum \(6+6\sqrt2\text{ cm}\) at \(45^\circ\); \(P=14\) at \(25.5^\circ,64.5^\circ\).

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