Amplitude, Period and Vertical Shift

Amplitude, Period and Vertical Shift

Secondary 4
TGM Original Questions

The constants in \(y=a\sin bx+c\) change the base graph in three predictable ways: \(a\) stretches it vertically, \(b\) squeezes it horizontally, and \(c\) slides it up or down. Read all three straight from the equation.

Features of \(y=a\sin bx+c\), \(y=a\cos bx+c\) and \(y=a\tan bx+c\) for \(a,b>0\)

Feature\(y=a\sin bx+c\) or \(y=a\cos bx+c\)\(y=a\tan bx+c\)
Midline\(y=c\)\(y=c\)
Amplitude\(a\)No amplitude
Period\(\dfrac{360^\circ}{b}\) or \(\dfrac{2\pi}{b}\)\(\dfrac{180^\circ}{b}\) or \(\dfrac{\pi}{b}\)
Maximum and minimum\(c+a\) and \(c-a\)No maximum or minimum

\(y=2\sin x\): the value of \(a\) doubles the height — amplitude \(2\), same period.

\(y=\sin 2x\): the value of \(b\) doubles the repeats — period \(\dfrac{2\pi}{2}=\pi\), same amplitude.

\(y=\sin x+1\): the value of \(c\) lifts the curve — midline \(y=1\), same amplitude and period.

Reading the features from an equation

EquationMidlineAmplitudeMax and minPeriod
\(y=3\sin 2x+1\)\(y=1\)\(3\)\(1+3=4\)
\(1-3=-2\)
\(\dfrac{360^\circ}{2}=180^\circ\)
\(\dfrac{2\pi}{2}=\pi\)
\(y=5-2\cos\dfrac{x}{2}\)\(y=5\)\(2\)\(5+2=7\)
\(5-2=3\)
\(\dfrac{360^\circ}{\left(\frac{1}{2}\right)}=720^\circ\)
\(\dfrac{2\pi}{\left(\frac{1}{2}\right)}=4\pi\)
\(y=3\tan 2x-1\)\(y=-1\)No amplitudeNone\(\dfrac{180^\circ}{2}=90^\circ\)
\(\dfrac{\pi}{2}\)

A negative value of \(a\) reflects the curve in its midline \(y=c\): the graph of \(y=-a\sin bx+c\) is the mirror image of \(y=a\sin bx+c\), with the same midline, amplitude and period.

Exam check

Amplitude is a positive distance. For \(y=2-3\cos 2x\) the amplitude is \(3\), not \(-3\) — the minus sign only reflects the curve in the midline \(y=2\).

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