Sketch $y = 2 \sin x$ for $0 \le x \le 2\pi$, labelling the maximum and minimum points. [2] Solv

Question

Sketch $y = 2 \sin x$ for $0 \le x \le 2\pi$, labelling the maximum and minimum points. [2] Solve $2 \sin x = \sqrt{3}$ for $0 \le x < 2\pi$. Give exact answers in radians. [2]

Accepted Answer

(a) Maximum: $(\frac{\pi}{2},2)$; minimum: $(\frac{3\pi}{2},-2)$ (b)$x=\frac{\pi}{3},\frac{2\pi}{3}$

Trigonometry

Trigonometry

Solution:

Solution locked