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Trigonometry

Trigonometry

Secondary 3
4 marks

  1. Sketch \(y = 2 \sin x\) for \(0 \le x \le 2\pi\), labelling the maximum and minimum points.

    [2]

  2. Solve \(2 \sin x = \sqrt{3}\) for \(0 \le x < 2\pi\). Give exact answers in radians.

    [2]

Solution:

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Answer:(a) Maximum: \((\frac{\pi}{2},2)\); minimum: \((\frac{3\pi}{2},-2)\) (b)\(x=\frac{\pi}{3},\frac{2\pi}{3}\)

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