Trigonometry - Basics of Trigonometric Ratios
Trigonometry - Basics of Trigonometric Ratios
In the diagram below, \(ABC\) is a right-angled triangle in which \(AB = 4\) cm, \(BC = 6\) cm and \(\angle BAC = 90^\circ\). \(BCD\) is a straight line. Find the exact form,
- \(\sin \angle ABC\),
- \(\cos \angle ACD\).
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Answer:(a) \(\frac{\sqrt{5}}{3}\), (b) \(-\frac{\sqrt{5}}{3}\)
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