Triangle $PQR$ is a right-angled triangle with $PQ = 10$cm, $QR = 6$cm and \(\angle PQR = 90^\

Question

Triangle $PQR$ is a right-angled triangle with $PQ = 10$cm, $QR = 6$cm and $\angle PQR = 90^\circ$. Given that $M$ is a point on $PR$ such that $\frac{MR}{PM} = \frac{5}{11}$, find, giving your answer as a fraction in its simplest form, the value of $\tan \angle MQR$, $\cos \angle PMQ$.

Accepted Answer

(a) $\tan\angle MQR=\frac{5}{12}$ (b) $\cos\angle PMQ=-\frac{5}{13}$

Trigonometry - Basics of Trigonometric Ratios

Trigonometry - Basics of Trigonometric Ratios

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