Solve each of the following equations. \({\frac{\sin 5x - \sin 3x}{\cos 5x + \cos 3x} = \frac{\sec^2

Question

Solve each of the following equations. ${\frac{\sin 5x - \sin 3x}{\cos 5x + \cos 3x} = \frac{\sec^2 x - 6}{4}, \ 0^\circ \leq x \leq 360^\circ}$ $ \sin x + \sin 4x + \sin 7x = 0$ , $0^\circ \le x \le 180^\circ$

Accepted Answer

(i) x = 78.7°, 258.7°, 135.0°, 315.0°; (ii) x = 0°, 40°, 45°, 80°, 90°, 135°, 160°, 180°

Trigonometry - Trigonometric Equations

Trigonometry - Trigonometric Equations

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