<p>Prove the following identities.</p>
<ol class="i-list"><li data-list-item-id="item-i"><div class="list-item-paragraph">\(\frac{5 + 4 \sin x - \cos^2 x}{\sin^2 x - 4} = \frac{\sin x + 2}{\sin x - 2}\)</div></li><li data-list-item-id="item-ii"><div class="list-item-paragraph">\(\frac{\sec^2 x + 2 \tan x}{1 - \tan^2 x} = \frac{1 + \tan x}{1 - \tan x}\)</div></li></ol>

\[\frac{5 + 4 \sin x - \cos^2 x}{\sin^2 x - 4} = \frac{\sin x + 2}{\sin x - 2}\]

\(\frac{5 + 4 \sin x - \cos^2 x}{\sin^2 x - 4} = \frac{\sin x + 2}{\sin x - 2}\)

\[\frac{\sec^2 x + 2 \tan x}{1 - \tan^2 x} = \frac{1 + \tan x}{1 - \tan x}\]

\(\frac{\sec^2 x + 2 \tan x}{1 - \tan^2 x} = \frac{1 + \tan x}{1 - \tan x}\)

Trigonometry - Proving and Simplifying Trigonometric Identities

Trigonometry - Proving and Simplifying Trigonometric Identities

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