Solve each of the following equations. $\cos 2x \sin \left( x - \frac{\pi}{3} \right) = 0$, \(-\pi

Question

Solve each of the following equations. $\cos 2x \sin \left( x - \frac{\pi}{3} \right) = 0$, $-\pi \leq x \leq \pi$ $2 \sin^2 x - 3 \sin x - 5 = 0$, $0 \leq x \leq 2\pi$

Accepted Answer

(i) $x = -\dfrac{3\pi}{4}, -\dfrac{2\pi}{3}, -\dfrac{\pi}{4}, \dfrac{\pi}{4}, \dfrac{\pi}{3}, \dfrac{3\pi}{4}$; (ii) $x = \dfrac{3\pi}{2}$

Trigonometry - Trigonometric Equations

Trigonometry - Trigonometric Equations

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