<p>Prove the following identities.</p>
<ol class="i-list"><li data-list-item-id="item-i"><div class="list-item-paragraph">\(\frac{2 \sin A + \sin 2A}{1 - \cos 2A} = \frac{\sin A}{1 - \cos A}\)</div></li><li data-list-item-id="item-ii"><div class="list-item-paragraph">\(\frac{1 - \cos 2A + \sin A}{\sin 2A + \cos A} = \tan A\)</div></li></ol>

\[\frac{2 \sin A + \sin 2A}{1 - \cos 2A} = \frac{\sin A}{1 - \cos A}\]

\(\frac{2 \sin A + \sin 2A}{1 - \cos 2A} = \frac{\sin A}{1 - \cos A}\)

\[\frac{1 - \cos 2A + \sin A}{\sin 2A + \cos A} = \tan A\]

\(\frac{1 - \cos 2A + \sin A}{\sin 2A + \cos A} = \tan A\)

Trigonometry - Compound and Double-Angle Identities

Trigonometry - Compound and Double-Angle Identities

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