Solve the equation ${{\left( 2\sin 2x \right)}^{\sin 2x+\cos 2x}}=1$, for $0\le x\le 2\pi $

Question

Solve the equation ${{\left( 2\sin 2x \right)}^{\sin 2x+\cos 2x}}=1$, for $0\le x\le 2\pi $.

Accepted Answer

$x=\frac{1}{12}\pi ,\,\frac{3}{8}\pi ,\,\frac{5}{12}\pi ,\,\frac{7}{8}\pi ,\,\frac{13}{12}\pi ,\,\frac{11}{8}\pi ,\,\frac{17}{12}\pi ,\,\frac{15}{8}\pi $

Trigonometry - Trigonometric Equations

Trigonometry - Trigonometric Equations