Express $3 \sin x - 2 \cos x$ in the form of $R \sin (x - \alpha)$, where $\alpha$ is in

Question

Express $3 \sin x - 2 \cos x$ in the form of $R \sin (x - \alpha)$, where $\alpha$ is in radians. Hence solve $3 \sin x - 2 \cos x = -2.5$ for $0 \leq x \leq 2\pi$.

Accepted Answer

sqrt(13) sin(x - 0.5880); x = 4.50, 6.11 rad

Trigonometry - Trigonometric Equations

Trigonometry - Trigonometric Equations

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