Solve each of the following equations. \(\sin^2 y + 2 \cos 2y = 2 \cos y, 0^\circ \leq y \leq 360^\c

Question

Solve each of the following equations. $\sin^2 y + 2 \cos 2y = 2 \cos y, 0^\circ \leq y \leq 360^\circ$ $4 \cos 2x + 2 \sin x = -2, 0 \leq x \leq 2\pi$

Accepted Answer

(i) $0^\circ,109.5^\circ,250.5^\circ,360^\circ$. (ii) $0.848,2.29,\dfrac{3\pi}{2}$ rad.

Trigonometry - Trigonometric Equations

Trigonometry - Trigonometric Equations

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