Trigonometry - Trigonometric Equations
Express \(5\) \(\sin 3x - 8\) \(\cos 3x\) in the form of \(R \sin(3x - \alpha)\) where \(\alpha\) is in radians.
Hence, solve \(5\) \(\sin 3x - 8\) \(\cos 3x = -6.5\) for \(0 \le x \le \frac{4}{3}\pi\).
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Answer:(i) \(\sqrt{89}\sin(3x-1.01)\) (ii) \(x=0.0840,\ 1.64,\ 2.18,\ 3.73\text{ rad}\) (3 s.f.)