Express $\cos x - 6$ $\sin x$ in the form of $R \cos(x + \alpha)$ where $\alpha$ is in

Question

Express $\cos x - 6$ $\sin x$ in the form of $R \cos(x + \alpha)$ where $\alpha$ is in radians. Solve $\cos x - 6$ $\sin x = 2$ for $0 \le x \le 2\pi$.

Accepted Answer

(i) $\sqrt{37}\cos(x+1.41)$ (ii) $x=3.64\text{ rad}$ or $x=6.11\text{ rad}$ (3 s.f.)

Trigonometry - Trigonometric Equations

Trigonometry - Trigonometric Equations

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