Show that $4-\cos{2\theta}+5\sin{\theta}=2\sin^2{\theta}+5\sin{\theta}+3$.[2] Hence, solve th

Question

Show that $4-\cos{2\theta}+5\sin{\theta}=2\sin^2{\theta}+5\sin{\theta}+3$.[2] Hence, solve the equation $4-\cos{2\theta}+5\sin{\theta}=0$ for $0 \leq \theta \leq 2\pi$.[5]

Accepted Answer

(a) $2\sin^2\theta+5\sin\theta+3$ (shown). (b) $\theta=\frac{3\pi}2$.

Trigonometry - Trigonometric Equations

Trigonometry - Trigonometric Equations

Solution:

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