Trigonometry - Trigonometric Equations

Trigonometry - Trigonometric Equations

IP 3

In triangle \(ABC\), \(a\), \(b\) and \(c\) are the opposite sides of the interior angles \(A\), \(B\) and \(C\), respectively.

Given that \(b \sin A + a \cos B = 0\), show that \(B = \frac{3}{4}\pi\).

Solution:

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Answer:\(B=\frac{3\pi}{4}\) (shown).

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