Trigonometry - Compound and Double-Angle Identities
Trigonometry - Compound and Double-Angle Identities
IP 3
In triangle \(ABC\), \(a\), \(b\) and \(c\) are the opposite sides of the interior angles \(A\), \(B\) and \(C\), respectively.
Show that \(\tan A + \tan B + \tan C \equiv \tan A \tan B \tan C\).
Solution:
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Answer:\(\tan A+\tan B+\tan C=\tan A\tan B\tan C\) (shown), where no angle is \(\frac\pi2\).
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