<p>Prove that&nbsp;\(2\cos{2\theta}+2\sin{2\theta}+2=2\cos{\theta}(2\cos{\theta}+\sin{\theta})\)</p>
<p>Hence solve \(2\cos{\theta}(2\cos{\theta}+\sin{\theta})=0\) for&nbsp;\(0 \leq \theta \leq 2\pi\).</p>

Prove that \(2\cos{2\theta}+2\sin{2\theta}+2=2\cos{\theta}(2\cos{\theta}+\sin{\theta})\)

Hence solve \(2\cos{\theta}(2\cos{\theta}+\sin{\theta})=0\) for \(0 \leq \theta \leq 2\pi\).

Trigonometric Equations

Trigonometry

International Baccalaureate Mathematics: Applications and Interpretation Standard Level

Trigonometry - Trigonometric Equations

Trigonometry - Trigonometric Equations