Trigonometry - Basics of Trigonometric Ratios

Trigonometry - Basics of Trigonometric Ratios

13 marks

A rectangle is inscribed in a circle of radius 3 cm and centre O,

The point \(P\ (x,y)\) is a vertex of the rectangle and also lies on the circle. The angle between (OP) and the x-axis is \(\theta\) radians, where \(0 \leq \theta \leq \frac{\pi}{2}\).

  1. Write down an expression in terms of \(\theta\) for
    1. \(x\) ;
    2. \(y\) .[2]

Let the area of the rectangle be \(A\).

  1. Show that \(A=18\sin{2\theta}\).[3]
    1. Find \( \frac{\rm{d}A}{\rm{d}\theta}\).
    2. Hence, find the exact value of \(\theta\) which maximizes the area of the rectangle.
    3. Use the second derivative to justify that this value of \(\theta\) does give a maximum.[8]

Solution:

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Answer:(a)(i) \(x=3\cos\theta\) (ii) \(y=3\sin\theta\) (b) \(A=18\sin2\theta\) (shown) (c)(i) \(36\cos2\theta\) (ii) \(\theta=\dfrac\pi4\) (iii) \(A''\left(\dfrac\pi4\right)=-72<0\), with zero endpoint areas, so a maximum.

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