Triangles with a common height

Triangles with a common height

Secondary 3
3 marks
TGM Original Questions

Points \(A,B,C\) lie on the same straight line, with \(AB=4\text{ cm}\) and \(BC=6\text{ cm}\). Triangles \(ADB\) and \(BDC\) share vertex \(D\). The area of triangle \(ADB\) is \(10\text{ cm}^2\).

  1. Find the area of triangle \(BDC\).[2]
  2. Explain why squaring the base ratio \(4:6\) would be incorrect here.[1]

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Answer:(a) \(15\text{ cm}^2\). (b) Equal heights give the base ratio directly; similarity is not given.

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