Techniques of Integration - Logarithmic Integrals of $\frac{f'(x)}{f(x)}$

$\displaystyle\displaystyle \displaystyle\int{\frac{x}{1+{{e}^{-2{{x}^{2}}}}}}\mathrm{ d}x$

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Answer:$\frac14\ln|1+e^{2x^2}|+C$

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Techniques of Integration - Logarithmic Integrals of \(\frac{f'(x)}{f(x)}\)